A vessel is full of milk. 1/3 of the solution is taken out and replaced with water. This process is repeated thrice. At the end of it, if 16 liters of milk remains, how much water will be present in the vessel?
The issue is requesting one to discover the sum of water left in the vessel after a cycle is rehashed threefold. The inquiry expresses that 1/3 of the arrangement is taken out and supplanted with water. This cycle is then outlined threefold. As one may know, the word threefold is equivalent to the number three. So rehashing the triple process is identical to rehashing the cycle multiple times. The issue additionally expresses that 16 liters of milk staying after the method rehashed numerous times. To locate the right answer, one would have to discover the measure of fluid in the vessel after each cycle. Lastly, see the extent of water left in the vessel.
Finding the response for the initial step ought to be generally simple. To make things more clear, let x be the first measure of milk in the vessel. The initial step is to discover how milk left after 1/3 of the final arrangement is eliminated and supplanted with water. After 1/3 of the milk is taken out and replaced with water, the measure of milk left ought to be (2/3)x. The condition should seem as though this: Measure of milk went = (2/3)x. This implies that solitary (2/3)x of the milk is left before the primary cycle finishes. The variable x can be subbed with a number later on when more advances are finished. For the time being, let x be the first measure of milk in the vessel.
Since the primary cycle has been addressed, the following stage is to discover how much fluid is available toward the subsequent cycle’s finish. The liquid measure after the next process can be dictated by increasing the number 2/3 with technique one. The condition should resemble this: 2/3*(2/3)x. The explanation one should duplicate 2/3 with (2/3)x is that the aftereffect of cycle one was (2/3)x, thus the condition 2/3*(2/3)x. The response to this condition ought to be (4/9)x. The technique to tackle this answer would be to increase the portions 2/3 by 2/3 (2/3*2/3). This should offer a response of 4/9. Since the variable x has no worth reason now, one can just add it to the arrangement towards the end. Subsequently, the measure of milk left in the vessel is (4/9)x.
Since one has addressed the first and second steps of the issue, the following stage is settled for the third step. In the third step, nothing isolates it from phase one and stage two, aside from the various qualities being utilized and the diverse arrangement of esteems that will happen. After the subsequent cycle, the measure of milk left in the vessel had diminished to (4/9)x. To make the right condition for stage three of this issue, one would have to duplicate the consequence of cycle two with 2/3. The state should appear this: Measure of milk left = 2/3*(4/9)x. The condition resembles this since one ought to have increased 2/3, with the aftereffect of cycle two (4/9)x. The response to this condition ought to be (8/27)x. The explanation being that 4/9*2/3 is 8/27. Before the end of the third cycle, the measure of milk in the vessel has lowered further, to a measure of (8/27)x. The x can indeed be added to the appropriate response toward the end, as it has an unknown value. Now we have to locate the missing value of x. The issue now expresses that the measure of milk towards the finish of each of the three cycles is 16 liters. On the off chance that 16 liters of milk stay present in the vessel after every one of the three methodologies, that implies x must be 54 liters. x is 54 liters since x was named as the first measure of milk in the vessel.
The last advance in tackling this issue is to locate the conclusive answer. Since the issue contained the fluids milk and water, one would have to settle for the other fluid. The solitary other fluid in this issue is water. To address the measure of water, one would have to set up another condition. The condition should resemble this: x – (8/27)x = (19/27)x. After the measure of water is discovered, the condition simply needs the x incentive to be subbed. Presently the condition should resemble this: (19/27)*54. The 54 is the aggregate sum of fluid in the vessel, and the 19/27, is the measure of water. If one somehow happened to tackle the condition, (19/27)*54 would be 38. To find this solution, one would have to just duplicate 19/27 with the number 54. This is the reason the appropriate response is 38 liters.